n^2+2n+4=7

Solution for n^2+2n+4=7 equation:

Simplifying
n2 + 2n + 4 = 7

Reorder the terms:
4 + 2n + n2 = 7

Solving
4 + 2n + n2 = 7

Solving for variable 'n'.

Reorder the terms:
4 + -7 + 2n + n2 = 7 + -7

Combine like terms: 4 + -7 = -3
-3 + 2n + n2 = 7 + -7

Combine like terms: 7 + -7 = 0
-3 + 2n + n2 = 0

Factor a trinomial.
(-3 + -1n)(1 + -1n) = 0

Subproblem 1
Set the factor '(-3 + -1n)' equal to zero and attempt to solve:

Simplifying
-3 + -1n = 0

Solving
-3 + -1n = 0

Move all terms containing n to the left, all other terms to the right.

Add '3' to each side of the equation.
-3 + 3 + -1n = 0 + 3

Combine like terms: -3 + 3 = 0
0 + -1n = 0 + 3
-1n = 0 + 3

Combine like terms: 0 + 3 = 3
-1n = 3

Divide each side by '-1'.
n = -3

Simplifying
n = -3
Subproblem 2
Set the factor '(1 + -1n)' equal to zero and attempt to solve:

Simplifying
1 + -1n = 0

Solving
1 + -1n = 0

Move all terms containing n to the left, all other terms to the right.

Add '-1' to each side of the equation.
1 + -1 + -1n = 0 + -1

Combine like terms: 1 + -1 = 0
0 + -1n = 0 + -1
-1n = 0 + -1

Combine like terms: 0 + -1 = -1
-1n = -1

Divide each side by '-1'.
n = 1

Simplifying
n = 1
Solution
n = {-3, 1}